T-SQL DATEDIFF Function – Microsoft SQL

Returns the number of date and time boundaries crossed between two dates

SQL DATEDIFF Syntax
DATEDIFF ( DatePart , StartDate , EndDate )

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate =’2007-
06-05′
SET @EndDate =’2007-
08-05′

SELECT DATEDIFF(Year, @StartDate, @EndDate) AS NewDate
Return Value = 0 Year

SELECT DATEDIFF(quarter, @StartDate, @EndDate) AS NewDate
Return Value =
1 quarter

SELECT DATEDIFF(Month, @StartDate, @EndDate) AS NewDate
Return Value = 2 Month

SELECT DATEDIFF(dayofyear,@StartDate, @EndDate) AS NewDate
Return Value = 61 day

SELECT DATEDIFF(Day, @StartDate, @EndDate) AS NewDate
Return Value = 61 Day

SELECT DATEDIFF(Week, @StartDate, @EndDate) AS NewDate
Return Value = 9 Week

SELECT DATEDIFF(Hour, @StartDate, @EndDate) AS NewDate
Return Value = 1464 Hour

SELECT DATEDIFF(minute, @StartDate, @EndDate) AS NewDate
Return Value = 87840 minute

SELECT DATEDIFF(second, @StartDate, @EndDate) AS NewDate
Return Value = 5270400 second

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate =’2007-06-
05
SET @EndDate =’2007-06-
06

SELECT DATEDIFF(millisecond, @StartDate, @EndDate) AS NewDate
Return Value = 86400000 millisecond

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